I need the answer asap plz!! A sample of water vapor has a pressure of 36.0 Pa and a temperature of 300.0 K. If the pressure is
reduced to 32.0 Pa, what will the new temperature be?

266.67  K

Explanation:

Recall the formula for ideal gasses:

P * V = n * R * T

from which a proportion can be obtained if the volume of the gas and its number of moles remain constant. This is:

T / P  = constant  and therefore T1 / P1 = T2/ P2

Then for our case:

300 / 36 = T2 / 32

solving for T2:

T2 = 300 * 32 / 36 = 266.67  K

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explanation:

newton's third law, for every action there is an equal and opposite reaction.