Dennis throws a volleyball up in the air. It reaches its maximum height 1.1s later. We can ignore air resistance. What was the volleyballs velocity at the moment it was tossed into the air.

The volleyball's velocity at the moment it was tossed into the air was 10.78 m/s

Explanation:

To determine the volleyballs velocity at the moment it was tossed in air, we will find the initial velocity of the volleyball.

From the one of the equations of motions for free falling bodies,

v = u + gt

Since the body here is thrown upwards, the equation becomes

v = u - gt

Where v is the final velocity

u is the initial velocity

g is acceleration due to gravity (Take g = 9.8 m/s²0

and t is the time.

From the question,

The volleyball reaches its maximum height 1.1s later.

(NOTE: At maximum height, the final velocity of the ball will be 0 m/s)

Therefore,

v = 0 m/s

t = 1.1 s

Putting the values into the equation

v = u - gt

0 = u - (9.8)(1.1)

u = 9.8 × 1.1

u = 10.78 m/s

This is the volleyball's initial velocity.

Hence, the volleyball's velocity at the moment it was tossed into the air was 10.78 m/s.  

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.