What angle would the axis of a polarizing filter need to make with the direction of polarized light of intensity 1.00 kW/m2 to reduce the intensity to 10.0 W/m2

The angle is 84.26⁰

Explanation:

The angle the axis of a polarizing filter need to make with the direction of polarized light is given by;

I = I₀Cos²θ

where;

I is the intensity of the polarized light transmitted from the polarizer

I₀ is the intensity of the polarized light incident on the polarizer

Given;

I₀ = 1.00 kW/m² = 1000 W/m²

I = 10 W/m²

Therefore, the angle is 84.26⁰

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