A man and his bike are 95 kg. His instantaneous speed at one point is 14m/s. The next time his speed is checked he is going 28m/s. If the second speed was taken 7 seconds later, what force must the man have given his bike to change the speed? What was the bicyclist’s final momentum?

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

answer is slate

hope this