A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s. It strikes a second hockey puck with a mass of 0.11 kg. The first hockey puck comes to rest after the collision. What is the velocity of the second hockey after the collision? (Round your answer to the nearest integer.)

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Idk just need points