An elevator accelerates upward at 1.2 m/s
2
.
The acceleration of gravity is 9.8 m/s
2
.
What is the upward force exerted by the
floor of the elevator on a(n) 92 kg passenger?
Answer in units of N
Normal force N pushing up and weight force mg pulling down.
Apply Newton's Second Law:
∑F = ma
N − mg = ma
N − (92 kg) (9.8 m/s²) = (92 kg) (1.2 m/s²)
N = 1012 N
Answer from: Quest
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Answer from: Quest
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