A long thin rod of length 2L rotates with a constant angular acceleration of 8.0 rad/s2 about an axis that is perpendicular to the rod and passes through its center. What is the ratio of the tangential acceleration of a point on the end of the rod to that of a point a distance L/2 from the end of the rod

Explanation:

angular acceleration ω = 8 rad /s²

tangential acceleration a = angular acceleration x radius of circle of rotation

For a point on the end of the rod , radius of circle = L .

tangential acceleration = 8 L .

For  a point a distance L/2 from the end of the rod, radius of circle = L /2 .

tangential acceleration = 8 L/2 = 4 L  .

It is so because angular acceleration will be same for this point , only radius changes .

required ratio = 8L / 4L

= 2.

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.