A Penny is dropped and falls freely from the top of the Empire State building 443m high. What information do you know? 1b. How long does it take to hit the ground? 1c. How fast is it moving right before it hits the ground?

1b. 9.51 s

1c. 93.18 m/s.

Explanation:

1a. From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 443 m

Acceleration due to gravity (g) = 9.8 m/s²

1b. Determination of the time it takes for the penny to get to the ground.

Height (h) = 443 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

443 = ½ × 9.8 × t²

443 = 4.9 × t²

Divide both side by 4.9

t² = 443/4.9

Take the square root of both side

t = √(443/4.9)

t = 9.51 s

1c. Determination of the speed of the penny before it hits the ground.

Initial velocity (u) = 0 m/s

Height (h) = 443 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =.?

v² = u² + 2gh

v² = 0² + 2 × 9.8 × 443

v² = 0 + 8682.8

v² = 8682.8

Take the square root of both side

v = √8682.8

v = 93.18 m/s

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