A cheetah accelerates at a rate of 6.9 m/s2. After 1.4s it is traveling at 35.7 m/s, what was the initial velocity?

-26.04 m/s

Explanation:

a=6.9m/s2, t=1/4s, vf=35.7m/s, vi=?

this is a dumb question because that means the cheetah slowed down the sped up at the same rate. :bruh:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s