A ball is thrown straight up in the air with a velocity of 12 m/s. Find the maximum height the ball reaches. Show your work

7.35 m

Explanation:

We can solve with kinematics or with energy.

Using kinematics, given:

v₀ = 12 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (12 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 7.35 m

Using energy instead:

PE = KE

mgh = ½ mv²

gh = ½ v²

h = v² / (2g)

h = (12 m/s)² / (2 × 9.8 m/s²)

h = 7.35 m

that would be because of both gravity and friction. so     c