what is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its specific heat capacity is 0.96 J/gC. What is the temperature change?

1) The specific heat is the heat required to be added to a unit mass of the substance to cause a unit rise in its temperature

2) The temperature change is 20.92°C

Explanation:

The given parameters are;

The mass of the substance, m = 2.50 g

The heat released by the sample, ΔQ = 12 calories = 50.208 J

The specific heat capacity of the substance, c = 0.96 J/(g·°C)

Therefore, we have;

Heat released, ΔQ = Mass, m × Specific heat capacity, c × Temperature change, ΔT

Substituting in the known values gives

50.208 J = 2.50 g × 0.96 J/(g·°C) × ΔT

ΔT = 50.208 J/(2.5 g× 0.96 J/(g·°C)) = 20.92°C

The temperature change = 20.92°C

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