A pitcher throws a baseball horizontally with a speed of 42 m/s. If the pitcher throws the baseball from a height of 1.25 meters, what is the resultant velocity of the ball right before it hits the ground? Include direction (angle).

v = 42.28 m/s

Explanation:

It is given that,

The horizontal speed of a baseball,

The pitcher throws the baseball from a height of 1.25 meters, h = 1.25 m

Firstly finding t i.e. the stone takes to reach the ground. Using second equation of motion as follows :

a = -g and u = 0

Vertical component of the velocity is :

Resultant velocity,

So, the resultant velocity of the ball before it hits the ground is 42.28 m/s.

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