A 250-kg motorcycle goes around an unbanked turn of radius 13.7 m at a steady 96.5 km/h. What is the magnitude of the net force on the motorcycle

Given:

As we know, the centripetal force is given by:

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By substituting the values, we get

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Thus the solution above is correct.

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13,116.35N

Explanation:

Magnitude of the net force on the motorcycle is expressed as;

F = mv²/r

m is the mass of the motorcycle

v is speed = 96.5km/hr

r is the radius = 13.7m

Convert speed to m/s:

96.5km/hr = 96.5×1000/1×3600

Speed = 96500/3600

Speed = 26.81m/s

Get the magnitude of the force:

F = 250×26.81²/13.7

F = 179,694.025/13.7

F = 13,116.35N

Hence the magnitude of the net force on the motorcycle is 13,116.35N

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

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explanation:

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