A red ball rolls for 6 meters across a sticky level surface and slows down to a stop. the ball was rolling at 36 meters per second when it began to roll across the sticky surface. find the acceleration, velocity final, the velocity initial, the velocity average, the distance the ball rolled, and the time of the balls roll across the sticky surface

The initial velocity of the ball is given as 36 m/s

The final velocity of the ball is given as 0 m/s

The distance the ball rolled is given as 6 meters

The acceleration is 108 m/s²

The time the ball rolls across the sticky surface is 1/3 seconds

The average velocity is 18 m/s

Explanation:

The initial velocity of the ball, u = 36 m/s

The final velocity of the ball, v = 0 m/s

The distance the ball rolled, s = 6 meters

The acceleration, a, is given by;

v² = u² - 2×a×s, where v = 0

u² = 2 × a × s

a = u²/(2 × s) =  36²/(2 × 6) = 108 m/s²

The time the ball rolls across the sticky surface is given by the following equation;

v = u - a×t, v = 0

∴ u = a×t

t = u/a = 36/108 = 1/3 seconds

The time the ball rolls across the sticky surface = 1/3 seconds

The average velocity = Distance/time = 6/(1/3) = 18 m/s

The average velocity = 18 m/s.

answerscientific theory;

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.