The velocity of an object as a function of time is given by v = (12.5t –7.2t2) + (4.3t3). What is its acceleration as a function of time?

Explanation:

The equation is not well written:

let the  velocity of an object as a function of time be given by

v = (12.5t - 7.2t²) + (4.3t³)

v(t) = 12.5t - 7.2t² + 4.3t³

acceleration is the  change in velocity with respect to time:

a(t) = d(v(t))/dt

a(t) = 12.5 - 2(7.2)t^2-1 + 3(4.3)t^3-1

a(t) = 12.5 -10.4t + 12.9t²

Hence the acceleration as a function of time t is expressed as;

a(t) = 12.5 -10.4t + 12.9t²

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