You throw a ball downward from a window at a speed of 1.7 m/s. How fast will it be moving when it hits the sidewalk 2.5 m below?

7.43m/s

Explanation:

Given parameters:

Initial velocity = 1.7m/s

Height  = 2.5m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply one of the motion equation. The most fitting one given the parameters is;

           V²  = U² + 2gh

where V is the final velocity

           U is the initial velocity

          g is the acceleration due to gravity = 9.8m/s

           h is the height

Input the parameters and solve;

    V² = 2.5² + 2(9.8)(2.5)

    V = 7.43m/s

b.

hope this : )