A 261 g object attached to a horizontal spring moves in simple harmonic motion with a period of 0.240 s. The total mechanical energy of the spring-mass system is 6.46 J. (a) What is the maximum speed of the object (in m/s)

maximum speed of the object =7.0 m/s

Explanation:

The total energy of the system is, given as

E = 1/2mω²A ²

but ωA=  ------ equation 1

Also. Linear speed is given as

v = ωA ……  equation 2

From equation  1 and 2 ,

v=

Total energy = 6.46J

mass = 261g to kg becomes  261/1000= 0.261kg

v=  

v=

v=

v=

v=7.0 m/s

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

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