A placekicker kicks a football at and angle of 40.0 degrees and the initial speed of the ball is 22 m/s. Ignoring air resistance, determine the maximum height that the ball attains.

The maximum height attains by ball is 48.64 meter.

The maximum height is given by using formula,

Where u is initial velocity, and value of

Given that,  

Substituting above values in formula.

Hence, the maximum height attains by ball is 48.64 meter.

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Explanation:

in this problem, we are expected to solve for the maximum height of a projectile (the ball)

Firstly, the expression for maximum height is

h = u ^2 *sin ^2 θ /2 g

Given data

initial velocity u=22m/s

angle of projection, θ= 40degrees

substituting into the expression we have

h = 22^2 *sin (40)^2 /2 *9.81

h = 484*0.413 /19.62

h =199.892 /19.62

h=10.18m

The maximum height is 10.18m

the answer is a. at the equator

c

explanation: