What is the velocity of the car, in meters per second, just after it hits a 165-kg deer initially running at 13 m/s in the same direction

Explanation:

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What is the velocity of a 900 kg car initially moving at 30.0 m/s, just after it hits a 165 kg deer initially running at 13.0 m/s in the same direction? Assume the deer remains on the car.

To solve this question, we will apply the law of conservation of energy as shown

m1u1+m2u2 = (m1+m2)v

m1 is the mass of the car = 900kg

u1 is the initial velocity of the car = 30m/s

m2 is the mass of the deer = 165kg

u2 is the initial velocity is the deer = 13m/s

v is the common velocity after collision

Substitute the given values into the formula as shown;

900(30)+165(13) = (900+165)v

27000+2145 = 1065v

29145 = 1065v

v = 29145/1065

v = 27.37m/s

Since both the car and deer have the same velocity after collision, hence the velocity of the car after hitting the deer is 27.37m/s

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