4. Vector A is 7.00 units in length and points along the positive x-axis. Vector B is 5.00 units in length and points along the negative x-axis. find the magnitude and direction of A+2B 1 point

Since the two vectors form a right angle, no components need to be found for the resultant vector - we already have them!

Vector R's x-component = 3.00 units

Vector R's y-component = 4.00 units

To solve for the magnitude of the displacement, use the distance formula: Square Root of [(3)^2 + (4)^2], which equals 5 units.

To solve for the direction of the displacement, plug in -4 (remember where it was pointing) for y and 3 for x. Tan-1(-4/3) = -53.13°, or 53.13° south of east.Please Mark as Brilliant

i think the answer would be reserve.