A ball is shot horizontally at 17.3m/s from the roof of a building 55.2 m tall, (use g = 9.8 m/s ^ 2) How far from the base of the building does the ball land?

Given that,

The initial speed of a ball, u = 17.3 m/s

It is shot from the roof of a 52 m tall building, h = 52 m

It is required to find the distance from the base of the building the ball land. Let the distance be d.

Final velocity of the ball, v = 0 (when it lands)

We can use third equation of motion to find it.

a = -g

So, it will land at a distance of 15.26 m.

waves moving from a fast medium to a slow medium will experience a reflection as light travels more slowly than red light. total internal reflection occurs when the critical angle is.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s