Riders on the Power Tower are launched skyward with an acceleration of 4g (where g is the free fall acceleration), after which they experience a period of free fall. What would be the apparent weight of a 65 kg rider during the launch and during the period of free fall, respectively?

The apparent weight of rider during skyward launch is 3185 N

The apparent weight of rider during free fall is zero

Explanation:

Given;

acceleration of the rider, a = 4g

mass of the rider, m = 65 kg

The apparent weight of rider during skyward launch is given by Newton's second law of motion;

R = W + F

Where;

W is weight of the rider

F is the upward force of the rider

R is the apparent weight of the rider

R = mg + ma

R = m (g + a)

R = 65(g + 4g)

R = 65(5g)

R = 65( 5 x 9.8)

R = 3185 N

The apparent weight of rider during free fall;

R = W - F

R = mg - ma

R = m(g -a)

During free fall , g = a

R = m(0)

R = 0

d.7.5cm is your answer

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards