A falling stone takes 0.31 seconds to travel past a window 2.2 meters tall. From what height above the top of the window did the stone fall

The height above the top of the window the stone fell is 2.57 m

Explanation:

Given;

time of stone fall, t = 0.31 s

distance the stone travel, y = 2.2m

The velocity of the stone when it travel past the window is given by;

v = y/t

v = 2.2 m / 0.31 s

v = 7.097 m/s

The height of fall with this final velocity is given by;

v² = u² + 2gh

where;

u is the initial velocity of the stone = 0

h is the height of fall

v² = 2gh

h = v² / 2g

h = (7.097² ) / (2 x 9.8)

h = 2.57 m

Therefore, the height above the top of the window the stone fell is 2.57 m

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