The speed required of a military jet when taking off from the deck of an aircraft carrier is dependent upon the speed of the carrier and the speed of the wind into which the carrier is moving. The takeoff speed required of a military jet relative to the deck of the carrier is 45 m/s. Determine the acceleration which a military jet must have to take off from the 126-m long runway of the USS Ronald Reagan aircraft carrier.

8.03 m/s

Explanation:

Given:

Final takeoff speed (v) = 45 m/s

Length of the runway (s) = 126 m

Initial speed of the jet (u) = 0 m/s (note: this isn't directly given but it is implied)

To find:

Acceleration of the jet (a)

Solution:

Here, we use the formula v² - u² = 2as

We have all the variables except a, so we can solve it for a.

Substituting the values of v, u, and s, we get:

(45)² - (0)² = 2(a)(126)

2025 = 252(a)

Therefore a = 2025/252 which comes out to be around 8.03 m/s2 which is the final answer.

Hope this helps! :D

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so the net speed of jerome will be given as

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so

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now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min