The derivative of a position function is a velocity function. The derivative of a velocity function is an acceleration function. A particle moves along a straight line. The distance of the particle from the starting point at time t is given by the function: s=t5−6t4 Find the value of t (other than 0 ) at which the acceleration is equal to zero. 6

Explanation:

Given the distance of the particle from the starting point at time t is given by the function: s=t⁵−6t⁴

velocity v(t) = ds/dt

Next is to get the acceleration function:

Next is to get the value of t at which the acceleration is equal to zero

Since t ≠ 0, hence;

20t -72 = 0

20t = 72

t = 72/20

t = 3.6secs

Hence the value of t (other than 0 ) at which the acceleration is equal to zero is 3.6secs

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

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