A dog walks 40. m west, then 10. m east and then 50. m south. What is the distance and displacement traveled?

The total distance traveled by the dog is 100 m and the displacement of the dog is 58.31 m.

The given parameters;

The displacement of the dog is the change in its initial position and the final position.

The resultant of the dogs position in x-direction: = 40 m - 10 m = 30 m

The resultant of the dogs position in y-direction: 50 m

The magnitude of the displacement;

R² = 30²  + 50²

R² = 3400

R = √3400

R = 58.3 m

The distance covered by the dog is the sum of all the positions of the dog.

Distance = 40 m + 10 m + 50 m

Distance = 100 m.

Thus, the total distance traveled by the dog is 100 m and the displacement of the dog is 58.31 m.

Learn more here:link

uranium fissions/breaks up giving out energy and neutrons

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.