A projectile is launched at an angle of 15 degrees above the horizontal and lands down range. For the same speed, what projection angle would produce the greatest downrange distance?

45°

Explanation:

Range is the horizontal distance travelled by an object undergoing projectile motion.

Range is given by the formula:

where u = velocity, g = acceleration due to gravity and θ = angle above the horizontal.

For angle of 15°:

We get a maximum range when sin(2θ) = 1

sin(2θ) = 1

2θ = sin⁻¹(1)

2θ = 90⁰

θ = 90°/2

θ = 45⁰

For angle of 45°:

the answer is d. 4

hope this

also the more points you give the faster your questions get answered