HURRY PLS 30 MINS LEFT A ball is rolling across the floor so that it is traveling along the positive x axis at 5.00 m/s. Due to the bend of the carpet fibers it experiences an acceleration of 1.25 m/s2 at an angle of -125.0o from the x axis.

A. What is the x component of the acceleration?

B. What is the y component of the acceleration?

C. What is the x component of the balls displacement after 3.00s?

D. What is the y component of the balls displacement after 3.00s?

E. What is the displacement of the ball over 3.00s?

A) aₓ = -0.717 m / s² ,  B)  a_{y} = -1.024 m / s², C) x = 11.77 m , D) y = -4.6 m ,

E)  d = 12.64 m

Explanation:

For this exercise we will use trigonometry to decompose the acceleration, we are told that

   a = 1.25 m /s²   with an angle tea = 125º in a clockwise direction

A) cos θ = aₓ / a

       aₓ = a cos θ

       aₓ = 1.25 cos (-125)

       aₓ = -0.717 m / s²

B)  sin θ = / a

     a_{y} = a sin θ

     a_{y} = 1.25 sin (-125)

    a_{y} = -1.024 m / s²

C) The displacement component

     x = v₀ₓ t + ½ aₓ t²

let's calculate

      x = 5 3 + ½ (-0.717) 3²

      x = 11.77 m

D) the y component of the displacement

      y = t + ½ t²

in this case the initial velocity is zero

      y = 0 + ½ (-1,024) 3²

      y = -4.6 m

E) Let's use the Pythagorean theorem

     d =√ (x² + y²)

     d = √ (11.77² + 4.6²)

     d = 12.64 m

its a 5.5 n

glad that