From the moment a 40 m/s fastball touches the catcher’s mitt until it is completely stopped takes 0.012 s. Calculate the average acceleration of the ball as it is being caught.

3333.33 m/s²

Explanation:

From the question given above, the following data were obtained:

Total Velocity (v) = 40 m/s

Total Time (t) = 0.012 s.

Average acceleration (a) =..?

Average acceleration can be defined as follow:

Average acceleration (a) = Total velocity (v) / total time (t)

a = v / t

With the above formula, we can obtain the average acceleration of the ball as shown below:

Total Velocity (v) = 40 m/s

Total Time (t) = 0.012 s.

Average acceleration (a) =..?

a = v / t

a = 40 / 0.012

a = 3333.33 m/s²

Therefore, the average acceleration of the ball is 3333.33 m/s².

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