to avoid an accident, a driver with a mass of 60kg applies his brakes and decelrates from 30m/s to 1m/s in 2 seconds. how much force was absorbed by his seat belt

Force absorbed by the seatbelt is : 870 N

Given data :

mass of body = 60 kg

Initial velocity ( V₁ ) = 30 m/s

Final velocity ( V₂ ) = 1 m/s

Time = 2 secs

Determine the force absorbed by the seat belt

Force = Mass * acceleration  --- ( 1 )

where ;

acceleration = Δ v / t   ( 2 )

Δ v = ( 30 - 1 ) = 29 m/s

t = 2 secs

Back to equation ( 2 )

acceleration = 29 / 2 = 14.5 m/s²

∴ Force exerted on seatbelt

F = m * a

  = 60 kg * 14.5 m/s²  =  870 N

Hence we can conclude that the force absorbed by his seatbelt is 870 N

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Explanation:

Net Force

The net force applied to an object of mass m that moves at an acceleration a is given by:

F=m.a

The acceleration can be calculated by the equations of the constant acceleration motion:

Where vf is the final speed, vo is the initial speed, and t is the time.

Substituting the given values:

The force absorbed by his seat belt:

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.