The table shows experimental data of the magnitude of four forces exerted on a 2kg object as it slides across a horizontal surface. Which of the following could represent the magnitude of the net force that is exerted on the object? Select two answers.

6N and 10N

Explanation:

The forces acting along the horizontal axis arw the horizontal force applied and the frictional force.

Frictional force is a force that opposes the horizontal force (moving force)

First we need to get the sum of force along the horizontal as shown

\sum Fx = Horizontal force - frictional force

\sum Fx = 8N - 2N

\sum Fx = 6N

Hence one of the magnitude of the net force exerted on the object is 6N

For the forces along the vertical component;

The forces are the weight, force of gravity(acting downward) and the normal force acting upward

Given

Weight = mass × acceleration die to gravity

Weight = 2×10 = 20N

Normal force = 10N

\sum Fy = (weight)-normal force

\sum Fy = (20)-10

\sum Fy = 20-10 = 10N

Hence the other net force acting on the object is 10N

The required options are 6N and 10N

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge