you are riding an elevator upwards at 2.20m/s. you have a balance accurately calibrated in newtons. when you hang a mass of 15.0 the balance, the reading of the balance is

Explanation:

Note: the unit for acceleration  in m/s^2

Also, the unit of the mass in the problem is assumed to be in kg

We are going to use newtons second law of motion which expresses the weight in an elevator as

F=ma

Given data

Acceleration of the elevator a= 2.2m/s^2

mass m = 15kg

substituting the data in the expression for force is

F=2.2*15

F= 33N

The reading of the balance is 33N

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