A tennis ball is thrown straight up at 45 m/s. Calculate and compare the displacement at 5 seconds and 6 seconds after its been thrown. *

The answer to your question is given below.

Explanation:

The following data were obtained from the question:

Velocity (v) = 45 m/s

Time 5 (t₅) = 5 s

Time 6 (t₆) = 6 s

Displacement at 5 s (d₅) =.?

Displacement at 6 s (d₆) =.?

1. Determination of the displacement after 5 s.

Velocity (v) = 45 m/s

Time 5 (t₅) = 5 s

Displacement at 5 s (d₆) =.?

Velocity = Displacement /Time

v = d₅ /t₅

45 = d₅ / 5

Cross multiply

d₅ = 45 × 5

d₅ = 225 m

2. Determination of the displacement after 6 s.

Velocity (v) = 45 m/s

Time 6 (t₆) = 6 s

Displacement at 6 s (d₆) =.?

Velocity = Displacement /Time

v = d₆ /t₆

45 = d₆ / 6

Cross multiply

d₆ = 45 × 6

d₆ = 270 m

Summary:

Time >>>>>> Displacement

5 >>>>>>>>> 225 m

6 >>>>>>>>> 270 m

From the calculations made above the displacement of the ball after 6 seconds is greater than the displacement after 5 seconds.

its a 5.5 n

glad that

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