A projectile is launched upward at 24° from the ground and lands 12.5 s later at the same height. Assuming no air resistance... What is the magnitude of the launch velocity?
How far from its original position did it land?

The  magnitude of the launch velocity is 149.3 m/s

The distance is 74.65 m

Explanation:

Given that,

Angle = 24°

Time =12.5 sec

We need to calculate the magnitude of the launch velocity

Using equation of motion

Put the value in to the formula

We need to calculate the distance

Using formula of distance

Put the value into the formula

Hence, The  magnitude of the launch velocity is 149.3 m/s

The distance is 74.65 m

the answer is b i think