A 55 kg boy is throwing a 0.23 kg baseball up in the air. He decides to see how high he can throw it and uses a timer to see how long the ball stays in the air. He throws the ball as hard as he can straight up in the air and finds that it takes 5.5 seconds to come back to him. How long did it take for the ball to reach its highest point? (half the time it was in the air)

2.75 s

Explanation:

From the question given above,

Total time (T) spent by the ball in air = 5.5 s

Time taken (t) to reach the greatest height =...?

Thus, we can obtain the time taken (t) for the ball to reach the greatest height as follow:

T = 2t

Where:

T is the total time spent by the ball in air.

t is the time taken to reach the greatest height

Total time (T) spent by the ball in air = 5.5 s

Time taken (t) to reach the greatest height =...?

T = 2t

5.5 = 2 × t

Divide both side by 2

t = 5.5/2

t = 2.75 s

Therefore, the time taken (t) to reach the greatest height is 2.75 s.

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.