A man driving a car traveling at 20 m/sec slams on the brakes and decelerates at 3.25 m/s^2. How far does the car travel before it stops?

Recall that

where and are initial and final velocities, respectively; is acceleration; and is the net displacement, or distance if the object is moving in a single direction.

The car has initial speed 20 m/s and acceleration -3.25 m/s². It comes to a stop, so it has 0 final speed. Then

0² - (20 m/s)² = 2 (-3.25 m/s²) ∆x

∆x = (20 m/s)² / (7.5 m/s²) ≈ 53.3 m

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