A woman driving a car traveling at 40 m/s slams on the brakes and decelerates at 4 m/s2. How far does the car travel before it stops?

The car goes, x = 200 [m]

Explanation:

In order to solve this problem we must use the following kinematic equation.

where:

Vf = final velocity = 0

Vi = initial velocity = 40 [m/s]

a = desacceleration = 4 [m/s^2]

x = distance traveled [m]

Note: The negative sign of the above equation indicates that the vehicle is slowing down

Now replacing:

0 = (40)^2 - (2*4*x)

(0 - 40^2) = - 8*x

x = 200 [m]

reserve is the answer

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