A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,x=1.33 m and 1,y=−2.89 m in a lettuce garden to another location, with position vector 2,x=3.07 m and 2,y=−4.33 m, where the lettuce appears to be tastier (but really is not; this turtle cannot see very well). The excursion takes 327 s to complete. What are the components and the magnitude of the turtle's average velocity in meters per second?

Answer the radiant sun;

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.