a net horizontal force of 5000N is applied to a stalled car whose mass is 1500kg. what will be the car's speed after 10s?

v=33.3ms⁻¹

Explanation:

F=ma

a=F/m

a=5000/1500

a=3.33ms⁻²

v=u+at

v=0+3.33×10

v=33.3ms⁻¹

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft