A golf ball is hit off the ground with a speed of 34.0 m/s at a 56.0° angle with the horizontal. If the
a. How high (in meters) does the ball rise?

m
b. If the ball lands on the ground at the same height that it was hit, how much time does
the ball spend in the air?

c. How many meters away does the ball land?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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