A cheetah accelerates from rest at a rate of 9 m/s^2 for 3s. How far does it travel in this time? Assume the cheetah moves in a straight line.

a) 27.0 m
b) 40.5 m
c) 13.5 m
d) 54.0 m

b) 40.5 m

Explanation:

Given:

v₀ = 0 m/s

a = 9 m/s²

t = 3 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (3 s) + ½ (9 m/s²) (3 s)²

Δx = 40.5 m

i would think klcio3

the answer is 3.1 his answer is wrong mines is right