An oil drop with a mass of 7.20 x 10^-116 kg is moving up at a constant speed of 2.50 m/s between two horizontal parallel plates. If the electric field strength between these plates is 2.20 x 10^4V/m, what is the magnitude of the charge on the oil drop?

the body's situation won't change the forces are equal opposit and on the same body

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1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//