1. A rocket is fired vertically from the launch pad with a net accelevation of 20m/s². If the atmosphere is
approximately 100km thick and considering that the
acceleration is constant
a) what is the time it takes for the rocket to leave the
atmosphere?
b) What speed does the rocket reach at that time?

Max height= 36000 meters

Total Time = 120 seconds

Explanation:

0 = U - at

U = at

U= 20*60

U= 1200 m/s

MAX altitude would be

(U²Sin²tita)/2g

Max height= 1200² *( SIN90)²/(2*20)

Time of FLIGHT

2 * 1200/20

2400/20

120 sec onds

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