At one moment during a walk around the block, there are four forces exerted upon Fido - a 10.0 kg dog. The forces are: Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)
Fnorm = 64.5 N, up
Ffrict = 27.6 N, left
Fgrav = 98 N, down

Resolve the applied force (Fapp) into horizontal and vertical components. Then add the forces up as vectors to determine the net force.

Explanation:

Given that,

Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)

Fnorm = 64.5 N, up

Ffrict = 27.6 N, left

Fgrav = 98 N, down

(a) Resolution of the applied force:

Horizontal component,

Vertical component,

(b) Net horizontal force :

It is positive, it will act in right side

Net vertical force :

Hence, it is clear that the net force is in horizontal direction i.e. 30.42 N due right side.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia