It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar had a constant acceleration of -3.9 m/s/s, determine the speed of the Jaguar before it began to skid to a stop. A.) 48 m/s
B.) -2262 m/s
C.) -48 m/s
D.) 2262 m/s

The Speed of the Jaguar will be "-48 m/s".

Side,

Acceleration,

As we know,

→

or,

→

→

By substituting the values, we get

→      

→      

→      

Thus the above speed i.e., option C) is correct.  

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option c is correct

Explanation:

we know that

2as=vf²-vi²

vf²=2as

vf=√2as

vf=√2*290*(-3.9)

vf=√-2262

vf=-47.6 which is nearly equals to -48 m/s

hope this will helps you

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered