Cupid fires an arrow that strikes St. Valentine, producing the usual sounds of harp music and bird chirping as
Valentine swoons into a fog of love. If Cupid hears this
telltale sound exactly one second after firing the arrow and
the average speed of the arrow is 40 m/sec, what was the
distance separating them? Take 340 m/sec for the speed of
sound

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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