A hummingbird is flying around and its velocity v as a function of time t is given in the graph below where rightwards is the positive velocity direction.
v (m/s)
4
3
2
1
→t (8)
1.5 2 2.5 3 3.5
0.51
-1
-2
What is the hummingbird's displacement Ax from t = 3.0 s to 3.5 s?

2 m

Explanation:

The following data were obtained from the question:

Time 1 = 3 s

Time 2 = 3.5 s

Velocity = 4 m/s (constant)

Displacement =?

Next, we shall determine the change in time. This can be obtained as follow:

Time 1 = 3 s

Time 2 = 3.5 s

Change in time = 3.5 – 3

Change in time = 0.5 s

Finally, we shall determine the displacement of the bird between 3 s and 3.5 s as follow:

Velocity = 4 m/s

Time = 0.5 s

Displacement =?

Velocity = Displacement /Time

4 = Displacement /0.5

Cross multiply

Displacement = 4 × 0.5

Displacement = 2 m

Therefore, the displacement of the birth between 3 and 3.5 s is 2 m.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2