How much energy is required to heat 70 g of water at 20°C to boiling (100°C) if the specific heat of water is 4.184 J/g °C? Formula is Q=MCAT
29,288 J
23,430 J
5,858 J
35,146 J

Explanation:

Hello,

In this case, since we compute the required energy via:

Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:

Therefore, the energy turns out:

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