A water pump that consumes 2 kW of electric power when operating is claimed to take in water from a lake and pump it to a pool whose free surface is 30 m above the free surface of the lake at a rate of 53 L/s. Determine if this claim is reasonable. (Round the final answer to one decimal place.)

The claim is not reasonable

Explanation:

From the question we are told that

The power consumed is

The height of the pool's free surface is

The rate is

Given that the rate is 53 liters in 1 second , let say the 1 liter is equivalent to 1 kg so 50 liter = 50 kg

So the workdone by the pump is mathematically represented as

=>    

=>      

So what this value is telling us is that 14700 J of work is done in one  second

and generally power is workdone per time thus the power consumed to move water at the given rate is 14.7 kW which is far greater than the power stated in the question so the claim is not reasonable

answer: he got 23

explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂