Interactive Solution 11.13 presents a model for solving this problem. A solid concrete block weighs 100 N and is resting on the ground. Its dimensions are 0.400 m x 0.250 m x 0.130 m. A number of identical blocks are stacked on top of this one. What is the smallest number of whole bricks (including the one on the ground) that can be stacked so that their weight creates a pressure of at least two atmospheres on the ground beneath the first block

The value is

Explanation:

From the question we are told that

The weight of the block is

The dimension of the block is

Generally two atmosphere is equivalent to

Generally 1 atm =

The area of the block would be evaluated using width and height because we need for the smaller surface to be in contact with the ground in order to maximize the pressure and minimize number of blocks

So

=>

Generally the force due to this blocks is mathematically represented as

Here N is the number of blocks

So

=>  

v 154.9= 0.9 length length s little over 154.9cm

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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